下周要上人教九年级英语Unit 4 What would you do?Reading部分的公开课，请问怎么才能把这堂课上好？

there is some troubles about me ,i don't know how to deal with it i hope someone can help me maybe i am a shy girl sometimes i cann't speak out what i want to say , i have a roommate the way she remark a strange is very quick ,i can say i don't like her very much ,so we don't communicate with each other very well even we can say we don't talk with each other except the necessary words but i don't why she always say something bad about me to others when my good friend tell me what she says about me i feel very anger but the only thing what i feel a litter happy is my other roommaters say the remark isn't right you shouldn't conside it i know many people will say to me you shouldn't conside what she says ,but you know if many people say it it will be true even though it isn't,can you give some advice hope to see the good news you have said that she was not your friend,if so, what are you worried about It is her fault,absolutely, just let it be After all , i believe ,you cant do such dirty things like her,right如果回答对您有用，请及时采纳。

主题曲及插曲《爱，很简单》，作曲陶喆，填词娃娃，演唱陶喆。

片尾曲《没那么简单》，作曲萧煌奇，填词姚若龙，演唱岑宁儿。

《爱，很简单》歌词：

忘了是怎么开始

也许就是对你

有一种感觉

忽然间发现自己

已深深爱上你

真的很简单

爱的地暗天黑 都已无所谓

是是非非无法抉择

没有后悔 为爱日夜去跟随

那个疯狂的人是我

I love you

无法不爱你 Baby

说你也爱我

I love you

永远不愿意 Baby 失去你

不可能更快乐

只要能在一起

做什么都可以

虽然世界变个不停

用最真诚的心

让爱变得简单

爱的地暗天黑 都已无所谓

是是非非无法抉择

没有后悔 为爱日夜去跟随

那个疯狂的人是我

I love you

一直在这里 Baby

一直在爱你

I love you

Oh yes I do

永远都不放弃

这爱你的权利

如果你还有一些困惑 Oh no

请贴着我的心倾听

听我说着 爱你

Yes I do

Come on now

One more time

I love you

Oh yes I do

一直在这里 Baby oh yeah

一直在爱你

I love you

永远都不放弃

这爱你的权利

剧情：

“地球男”张申然（古天乐饰）向程子欣（高圆圆饰）求婚失败，最终不敌“火星男”方启宏（吴彦祖饰）。申然重返情场，便和“女股神”杨鸯鸯（杨千嬅饰）展开恋情。

这一次，又遭遇劲敌“法国男”程子建（周渝民饰）。申然害怕悲剧重演，欲和鸯鸯速定终身。天意弄人，子欣竟是鸯鸯下属，重新出现在申然眼前，令他方寸大乱。看似花心的申然，实则情伤不浅。

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(1)ρ(x,a)=|e^x-a|-a|x-lna|=(a-e^x)-a(lna-x)(x<lna)

=(e^x-a)-a(x-lna)(x>lna)

当x<lna时，f'(x)=-e^x+a>0;当x>lna时，f'(x)=e^x-a>0

所以f(x)在R上单调递增

而f(lna)=0

所以f(x)在R上只有1个零点

(2)F(x)=|e^x-a|-a|x-lna|-|e^x-b|+b|x-lnb|

=(a-e^x)-a(lna-x)-(b-e^x)+b(lnb-x)=(a-b)x+a-alna-b+blnb(x<lna)

=(e^x-a)-a(x-lna)-(b-e^x)+b(lnb-x)=2e^x-(a+b)x-a-b+alna+blnb(lna<x<lnb)

=(e^x-a)-a(x-lna)-(e^x-b)+b(x-lnb)=(b-a)x-a+alna+b-blnb(x>lnb)

当x<lna时，F'(x)=a-b<0

当lna<x<lnb时，F'(x)=2e^x-(a+b)

在此情况下，当lna<x<ln[(a+b)/2]时，F'(x)<0;当ln[(a+b)/2]<x<lnb时，F'(x)>0

当x>lnb时，F'(x)=b-a>0